Higher-Dimensional Stable Bernstein Theorems
We outline the strategy for the unconditional stable Bernstein theorem in dimensions \(n=3,4,5\). The argument has three main steps: a conformal change producing positive spectral bi-Ricci curvature, the construction of \(\mu\)-bubbles, and uniform area bounds for these bubbles via spectral Ricci estimates. The conformal and spectral curvature estimates are proved in §5.2.1; the \(\mu\)-bubble reduction is treated in §5.2.2, and the spectral Ricci estimates are recorded in §5.2.6.
Step 1: Conformal change and spectral bi-Ricci curvature. Let \(M^n\hookrightarrow \mathbb{R}^{n+1}\) be a complete, two-sided, stable minimal immersion. Fix \(0\in M\) and write \(r(x)=|x|\) for the Euclidean distance from the origin. Following Schoen–Simon–Yau and the recent stable Bernstein literature, we pass to the conformal metric
where \(g\) is the induced metric. Stability of \(M\) yields a spectral inequality for the conformal Laplacian with a curvature potential. To state it uniformly in dimension, we introduce the bi-Ricci curvature.
Let \((N,g)\) be a Riemannian manifold of dimension \(m\geq 2\). For orthonormal \(v,w\in T_pN\), define
As functions on \(N\), we write \(\mathrm{BiRic}\) and \(\mathrm{Ric}\) for the minimum over unit directions (with \(v\perp w\) for \(\mathrm{BiRic}\)):
In dimension \(m=3\), the bi-Ricci curvature is independent of the chosen orthonormal pair:
This is why the three-dimensional part of the argument is often stated as a spectral scalar-curvature condition.
We use spectral curvature condition to mean a lower bound for the first eigenvalue of a Schrödinger operator whose potential is built from one of these curvature quantities. The coefficient depends on the dimension and on the normalization used in the \(\mu\)-bubble argument.
In the conformal metric \(\tilde g=r^{-2}g\), stability gives the concrete inputs needed below: for \(n=3\),
by the conformal scalar-curvature computation in §5.2.1, while for \(n=4\),
after the corresponding conformal bi-Ricci normalization.
Thus, after conformal reparametrization, the problem is reduced to studying a manifold with non-negative spectral bi-Ricci curvature (in dimension three this is precisely non-negative spectral scalar curvature). This replaces the extrinsic curvature input of the minimal hypersurface by an intrinsic spectral curvature hypothesis on \((M,\tilde{g})\).
Step 2: Construction of \(\mu\)-bubbles. The second step is to produce separating hypersurfaces inside a collar of \((M,\tilde{g})\) with controlled geometry. These are \(\mu\)-bubbles.
Classically, a soap bubble is a hypersurface of constant mean curvature (CMC) enclosing a prescribed volume—the archetypal prescribed mean curvature problem. More generally, one studies hypersurfaces whose mean curvature is a prescribed function of position and geometry; Gromov introduced and systematically used such constructions in his work on scalar curvature, naming them \(\mu\)-bubbles (the name reflects the measure \(\mu\) specifying the prescription). In the present setting, one considers a Riemannian manifold \((N,g)\) with boundary \(\partial N=\partial_+N\cup\partial_-N\) and seeks a domain \(\Omega\subset N\) whose boundary \(\Sigma=\partial\Omega\setminus\partial_-N\) (the \(\mu\)-bubble) solves a variational problem of prescribed mean curvature type: schematically, one minimizes a functional of the form
for a weight \(w\) (often the first eigenfunction of a suitable operator on \(N\)) and a carefully chosen function \(h\) determined by the curvature of \(N\). Under the spectral bi-Ricci condition from Step 1, such a minimizer exists and provides a \(\mu\)-bubble \(\Sigma\) separating \(\partial_-N\) from \(\partial_+N\) (Theorem 5.2.8).
In recent years, \(\mu\)-bubbles have become a central tool in positive scalar curvature geometry and have led to breakthroughs in the classification of manifolds with positive scalar curvature, the resolution of the Riemannian positive mass theorem in many settings, and the stable Bernstein program in dimensions three through five. The method is flexible: by choosing the prescription (the \(\mu\)-data and the function \(h\)), one encodes the desired curvature inequality into the Euler–Lagrange equation of the \(\mu\)-bubble.
Step 3: Volume and diameter estimates for \(\mu\)-bubbles. The third step controls the size of each \(\mu\)-bubble \(\Sigma\). This is analogous in spirit to the dimension reduction in the Schoen–Yau proof of the positive mass theorem: one does not work directly on the full ambient manifold, but on a hypersurface of one dimension lower whose geometry is more rigid.
After Step 2, each \(\mu\)-bubble \(\Sigma\) is a closed hypersurface in \(N\) (of dimension \(m-1\)) lying in a thin collar between \(\partial_-N\) and \(\partial_+N\). Using the construction and the spectral bi-Ricci hypothesis on \(N\), one shows that \(\Sigma\) itself carries a spectral non-negative Ricci condition: the first eigenvalue of an operator of the form \(-\Delta^\Sigma+\alpha\,\mathrm{Ric}\) is non-negative for some \(\alpha\in(0,2)\) depending on \(n\). One then studies manifolds with spectral non-negative Ricci curvature by methods similar to Bray’s proof of the Bishop–Gromov comparison: spectral bounds on \(-\Delta+\mathrm{Ric}\) imply diameter and volume upper bounds (Theorem 5.2.13 and the discussion in §5.2.6). In particular, each component of \(\partial\Omega\) has area and intrinsic diameter bounded by constants depending only on the spectral bound, not on the size of the collar.
Conclusion of the proof. Combining Steps 1–3, one obtains separating \(\mu\)-bubbles in long conformal annuli with uniform \(\tilde g\)-area and diameter bounds. As explained in the proof of the Euclidean volume-growth estimate in §5.2.6, these conformal estimates imply
for every \(\rho\gt{}0\). Thus the \(\mu\)-bubble argument supplies the area-growth hypothesis needed for the stable Bernstein theorems with area growth, and the cited classification results force \(M\) to be an affine hyperplane. This completes the proof sketch; the conformal and spectral bi-Ricci estimates used in Steps 1–3 are proved in §5.2.1.
Conformal change of the metric on minimal hypersurfaces
Let \(M^n\hookrightarrow \mathbb{R}^{n+1}\) be a complete, two-sided, stable minimal immersion with induced metric \(g=\varphi^*\delta\). Fix \(0\in M\) and write \(r(x)=|x|\). Throughout we use the conformal metric
We use the bi-Ricci convention fixed above: \(\mathrm{BiRic}\) denotes the minimum over orthonormal two-frames, and in dimension three \(\mathrm{BiRic}=\frac12 R\).
Let \(M^n\hookrightarrow \mathbb{R}^{n+1}\) be a complete, two-sided, stable minimal immersion with induced metric \(g=\varphi^*\delta\). Then, the conformal metric \(\tilde{g}=r^{-2}g\) satisfies
where \(\tilde{\Delta}\) is the conformal Laplacian and \(\widetilde{\mathrm{BiRic}}\) is the conformal bi-Ricci curvature.
Under a general conformal change \(\tilde{g}=f^{-2}g\), we first relate the intrinsic Hessian on \(M\) to the ambient Euclidean Hessian.
Let \(M^n\subset\mathbb{R}^{n+1}\) be a hypersurface with unit normal \(\nu\), second fundamental form \(A(X,Y)=\langle D_X Y,\nu\rangle\), and ambient connection \(D\). For \(f\in C^\infty(M)\) and tangent vector fields \(X,Y\) on \(M\),
where \(D^2 f(X,Y):=D_X(D_Y f)\) and \(\nabla^M\) is the Levi-Civita connection of the induced metric.
Proof. Write the ambient gradient \(Df=\nabla^M f+\langle Df,\nu\rangle\,\nu\), so \(\nabla^M f\) is the tangential part. By direct computation,
◻
For the conformal metric \(\tilde{g}=e^{2\varphi}g\), the change of Riemannian curvatures is given by
where
For \(\varphi=-\log r\), we have
So
For the conformal metric \(\tilde{g}=r^{-2}g\) with \(r(x)=|x|\), \(\varphi=-\log r\), the conformal curvatures satisfy
We compute \(\mathrm{BiRic}\) on \(M\) using the Gauss equation.
Let \(\{e_1,\ldots,e_n\}\) be a local orthonormal frame on a minimal hypersurface \(M^n\subset\mathbb{R}^{n+1}\). Then
Proof. Using the Gauss equation, we compute
where the last line follows since \(\mathrm{tr}\,A=0\) for a minimal hypersurface. ◻
Now, we choose \(\tilde{e}_1\) and \(\tilde{e}_2\) such that \(\widetilde{\mathrm{BiRic}}(\tilde{e}_1,\tilde{e}_2)\) takes the minimum value. Then, we have
For \(n \geq 3\), we have
Proof. Recall that
Since \(\langle \vec x,\nu\rangle = r\,dr(\nu)\), we use Young’s inequality to obtain
Combined with (5.2.1) and the fact that
we have
Now we compute, using the fact that \(\operatorname{Tr} A=0\),
where we took
in the last line. Hence, for \(n\geq 3\), we have
Therefore,
and the proposition follows. ◻
For any \(\psi \in C_c^{0,1}(N,\tilde g)\), we have
Proof. Recall that in the conformal metric, we have
Then the stability inequality for \(M\) implies
for any \(f \in C_c^{0,1}(N,\tilde g)\). We take
for \(\psi \in C_c^{0,1}(N,\tilde g)\). Then
so
We have
Since
we have
Finally, we use integration by parts and the displayed formula for \(\tilde\Delta\log r\) below to compute
Recall that we have the following
Altogether, we obtain
as desired. ◻
For \(3\leq n\leq5\), we have
in the spectral sense.
Proof. Combining Proposition 5.2.6 with Proposition 5.2.5, for every \(\psi\in C_c^{0,1}(N,\tilde g)\) we get
where
Since \(0\leq |dr|^2\leq1\) and \(C_1\leq0\) for \(3\leq n\leq5\), the right-hand side is bounded from below by
This proves the claimed spectral lower bound. ◻
Construction of the \(\mu\)-Bubble
Suppose \((N^n,g)\), \(3\leq n\leq4\), is a compact manifold with boundary \(\partial N=\partial_+N\cup\partial_-N\). Assume that there are \(0\lt{}a\leq 2\) and a positive smooth function \(w\) such that
Suppose that the distance between \(\partial_-N\) and \(\partial_+N\) is bounded below by \(5\pi\). Then one can find a smooth \(\mu\)-bubble \(\Sigma\) separating \(\partial_-N\) from \(\partial_+N\) such that, for every \(\psi\in C_c^\infty(\Sigma)\),
Equivalently, in the spectral sense,
The constant \(1\) is only a normalization and can be replaced by any positive constant after rescaling the metric.
Second variation of weighted area functional
The minimizer to the following functional
satisfies the following equation
for any smooth function \(\phi\) on \(\Sigma\).
Given a domain \(\Omega\) in \(N\), we do a variation \(\Omega_t\) under vector field \(V\) and denote \(\Sigma_t=\partial\Omega_t\backslash \partial_-N\) and \(\Sigma=\Sigma_0\). We choose \(V\) such that \(\nabla_{V}V=0\) and \(V=\phi \nu\) along \(\Sigma\). (Note that in general, we do not have \(V\bot \Sigma_t\) for every \(t\).)
The following first and second variation formulas hold:
The first variation is straightforward.
Hence, the stationary gives us the formula
For the derivative of \(\int_{\Sigma} w\,\mathrm{div}^\Sigma(V^T)\,d\mathcal{H}^{n-1}\), we rewrite it using integration by parts as
After differentiating,
where we have used \(\nabla_{V}V=0\). Note that we have
Then, the derivative of \(\int_{ \Sigma} \left< \nabla^\Sigma w, \phi \nabla_{V}\nu \right>\) is
Now, we can compute the second variation. Note that we can use \(V\left< V, \nu \right> =0\).
For the Hessian, we have
using integration by parts, we have
This is the weighted-area second variation formula used below.
Properties of the minimizer
Suppose \(\Omega\) is the minimizer to \(\mathcal{A}\). Assume that the weight is \(W=w^a\), where \(0\lt{}a\leq 2\), \(w\gt{}0\), and
We also assume that the function \(h\) satisfies the following condition:
Then, for any \(\psi\in C_c^\infty(\Sigma)\), we have
We can also write it as
Proof. Suppose \(\Omega\) is the minimizer to \(\mathcal{A}\). In the spectral bi-Ricci application the weight in the functional is
and we consider
Then
Hence
The first variation gives
Put
Then \(H=h-av\), and hence
We also need to compare the ambient and intrinsic Laplacians of the weight \(W=w^a\). Along \(\Sigma\),
Thus
Since \(\Sigma\) is stable for the weighted functional, the second variation formula with weight \(W\) gives, after moving the potential terms to the right-hand side,
The final term is obtained by combining the Laplacian comparison contribution \(-a(a-1)v^2\) with the \(ahv\) term. Since \(0\lt{}a\leq2\), it is nonnegative and can be discarded.
It remains to estimate the left-hand side of (5.2.2). After substituting \(\phi=w^{-a/2}\psi\), it becomes
and Young’s inequality with \(\varepsilon=(4-a)^{-1}\) gives the estimate. Therefore,
Combining this estimate with (5.2.2) and the spectral inequality \(-a\Delta^Nw+\mathrm{BiRic}_Nw\geq w\) gives
Now, we need to use \(|A|^{2}+\mathrm{Ric}_N(\nu,\nu)\) to bound \(\mathrm{BiRic}_N\).
We have the following inequality:
This is the extension of the usual Schoen–Yau trick. Recall that we have (for \(n=3\))
This is exactly the same as the inequality in the lemma.
Proof. Suppose \(e_1\in T_p\Sigma\) is a unit direction where \(Ric_\Sigma\) attains its minimum. Using the Gauss equation, we have
Note that we have
By the choice of \(e_1\), \(\mathrm{Ric}_\Sigma=\mathrm{Ric}_\Sigma(e_1,e_1)\). Hence, we have
Equivalently,
which is the desired inequality. ◻
Now, we go back to our inequality. When \(3\leq n\leq 4\), we have \(\frac{6-n}{4}\geq \frac{1}{2}\) and therefore
Together with the condition for \(h\), \(1+h^{2}-2|\nabla^N h|\geq0\), we have
Hence
This is the desired inequality. ◻
Completion of the \(\mu\)-Bubble Construction
To prove Theorem 5.2.8, choose \(h\) by
where \(\tilde{d}(x,\partial_-N)\) is a smoothing of \(d_N(x,\partial_-N)\) with \(\mathrm{Lip}\,\tilde{d}\leq 2\). We denote \(\varphi(x)=\frac{\tilde{d}(x,\partial_-N)}{4}-\frac{\pi}{2}\). Then
To show the existence of the minimizer, fix a domain \(\Omega_0\) containing \(\partial_-N\) but not \(\partial_+N\) such that \(\partial \Omega_0\) lies in \(\tilde{d}(x,\partial_-N)\lt{} 4\pi\). We consider minimizing the following (relative) energy functional
The direct method gives a minimizer in the corresponding relative homology class. Since \(3\leq n\leq4\), the free boundary part \(\Sigma=\partial\Omega\setminus\partial_-N\) is smooth after the usual regularity theory for prescribed-mean-curvature hypersurfaces. The choice \(d_N(\partial_+N,\partial_-N)\geq5\pi\) gives enough room for the smoothing \(\tilde d\) and hence for the above choice of \(h\). Applying the stability inequality from the preceding proposition proves Theorem 5.2.8.
Diameter estimate and volume estimate under spectral Ricci curvature bound
The following result of Antonelli–Xu [AX24] gives the radius/diameter and volume estimates under a spectral Ricci lower bound. In this subsection \(\mathrm{Ric}_N(v,v)\) denotes the Ricci tensor on a unit vector; when \(\mathrm{Ric}_N\) appears without arguments in a spectral inequality, it means the smallest eigenvalue of the Ricci tensor. The bi-Ricci notation is the one fixed above. In the low-dimensional range considered here, the minimizers appearing in the \(\mu\)-bubble arguments are smooth. The parameter \(\alpha\) below denotes the coefficient of the spectral Laplacian term.
Let \((N^n,g)\) be a compact smooth Riemannian manifold, \(3\leq n\leq 5\), and let
Suppose that there is a positive smooth function \(u\) such that
Let \((\widetilde N,\tilde g)\) be the universal cover and let \(\tilde u\) be the lift of \(u\). Then the diameter upper bound is
Moreover the sharp volume upper bound is
where \(S^n\) denotes the unit round sphere. In particular \(\pi_1(N)\) is finite. If equality holds in the volume estimate, then \(\tilde u\) is constant and \(\widetilde N\) is the round sphere of radius \(\lambda^{-1/2}\).
Let \((N^n,g)\) be complete, not assumed compact, with \(3\leq n\leq 5\). If \(n\gt{}3\) and \(0\leq\alpha\lt{}\frac{4}{n-1}\), or if \(n=3\) and \(0\leq\alpha\leq2\), and if (5.2.3) holds for some positive smooth \(u\), then \(N\) is compact. Moreover \(\pi_1(N)\) is finite and, for the universal cover \(\widetilde N\),
In particular \(|N|\leq \lambda^{-n/2}|S^n|\). In addition there is a constant \(C=C(n,\alpha)\) such that
Proof. This is precisely the complete-case corollary in [AX24], based on Xu’s subcritical spectral Bonnet–Myers theorem. The latter gives compactness and the uniform bound \(\mathrm{diam}(N)\leq C(n,\alpha)\lambda^{-1/2}\) in the stated range. Once compactness is known, Theorem 5.2.13 applies and gives (5.2.4) and (5.2.5). Since \(N\) is the quotient of \(\widetilde N\) by a finite group of deck transformations, the same volume upper bound also holds for \(N\). ◻
Even in the larger sharp range \(0\leq\alpha\leq (n-1)/(n-2)\), if \(N\) is complete and the positive function \(u\) in (5.2.3) satisfies \(0\lt{}\inf_N u\leq\sup_Nu\lt{}\infty\), then Corollary 5.2.17 below proves compactness directly. Thus noncompact examples in the super-subcritical range must have \(u\) degenerating at infinity.
Weighted geodesic proof of the diameter estimates.
We also record the weighted-geodesic calculation, since it gives another way to see the Bonnet–Myers part.
For a positive function \(u\) on \((M^m,g)\), we define the weighted geodesic distance from \(p\) to \(q\) by
where the infimum is taken over piecewise smooth curves from \(p\) to \(q\). As above, \(\mathrm{Ric}_M\) in a spectral inequality denotes the smallest eigenvalue of the Ricci tensor, while \(\mathrm{Ric}_M(T,T)\) denotes the tensor on the vector \(T\).
Let \((M^m,g)\) be complete, \(m\geq3\), and suppose that \(u\gt{}0\) satisfies
Let \(\alpha:[0,l]\to M\) be an \(L_u^\alpha\)-minimizing curve from \(p\) to \(q\), parametrized by \(g\)-arclength, and assume first that \(q\) is not a weighted cut point along \(\alpha\). Then the following hold in the barrier sense at \(q\).
If \(0\leq\alpha\lt{}4/(m-1)\), then for every \(C^1\) function \(\psi\) on \([0,l]\) with
we have
where
In particular, choosing
gives
If \(0\leq\alpha\leq (m-1)/(m-2)\), then for every \(C^1\) function \(\psi\) with
we have
Proof. Let \(T=\alpha'\) and put
Then \(L_u^\alpha\) is exactly the distance function of the conformal metric \(\tilde g\). Write
Along \(\alpha\) we have, by the definition of \(\tilde g\) and of the distance function \(\rho\),
We first compute \(\tilde\Delta\rho\) in the conformal metric. Choose a \(\tilde g\)-parallel orthonormal frame along \(\alpha\),
and write \(\tilde E_i=u^{-\alpha}e_i\). Thus \(e_1,\ldots,e_{m-1},T\) is \(g\)-orthonormal and \(e_i\perp T\). Let \(\phi\) be a test function with \(\phi(0)=0\) and \(\phi(l)=1\), and set
These fields vanish at \(p\) and equal \(\tilde E_i(q)\) at \(q\). Hence the ordinary second variation formula for the \(\tilde g\)-distance gives, for \(1\leq i\leq m-1\),
The missing \(m\)-th direction is radial and contributes nothing, since \(\tilde\nabla^2\rho(\tilde T,\tilde T)=0\) away from the cut locus. Summing the preceding inequality over the transverse directions gives
Here we used \(d\tilde s=u^\alpha ds\), \(\tilde T\phi=u^{-\alpha}\phi_s\), and \(\widetilde{\mathrm{Ric}}(\tilde T,\tilde T)=u^{-2\alpha}\widetilde{\mathrm{Ric}}(T,T)\).
Now return to the original metric. The conformal Laplacian formula for \(\tilde g=e^{2\log u^\alpha}g\) gives, at \(q\),
Combining (5.2.10) and (5.2.11), we get
Now rewrite the curvature term in (5.2.12) in the original metric. The conformal Ricci formula is
The conformal connection formula is
Applying it to the \(\tilde g\)-geodesic equation \(\tilde\nabla_{\tilde T}\tilde T=0\) gives
and therefore
Using this in the Ricci formula gives the pointwise identity along \(\alpha\)
The endpoint term in (5.2.12) is written in the same \(u(q)^{2\alpha}\int u^{-\alpha}(\cdots)\,ds\) scale as
because \(\phi(0)=0\) and \(\phi(l)=1\). Substituting (5.2.13) into (5.2.12) and expanding this total derivative gives the original-metric formula
Using (5.2.6) and \(\mathrm{Ric}_M(T,T)\geq \mathrm{Ric}_M\), along the curve
Together with
this gives
Only at this point do we change the test function. The subcritical estimate uses the substitution
Thus
Inserting this into (5.2.15) cancels the weight \(u^\alpha\) and gives
Since \(|\nabla u|^2\geq u_s^2\), this implies
When \(\alpha\lt{}4/(m-1)\), Cauchy’s inequality gives
This proves (5.2.7); the sine choice gives (5.2.8).
For the bounded-\(u\) diameter estimate one uses a different exponent. Put
Then
Substituting this into (5.2.15), the cross term cancels exactly and we obtain
If \(\alpha\leq (m-1)/(m-2)\), the two terms involving derivatives of \(u\) are nonpositive. Dropping them gives (5.2.9). ◻
Let \((M^m,g)\) be complete, \(m\geq3\), and suppose \(u\gt{}0\) satisfies (5.2.6). If
then
In particular \(M\) is compact.
Proof. Assume first that two points \(p,q\) are joined by an \(L_u^\alpha\)-minimizing curve \(\alpha:[0,l]\to M\) parametrized by \(g\)-arclength. Let \(x=\alpha(l/2)\). The weighted excess
has a local minimum at \(x\). Using the two subsegments of \(\alpha\) as barriers and applying (5.2.8) to each half, we get, in the viscosity sense,
Therefore \(l\leq \pi\sqrt{C_{m,\alpha}/((m-1)\lambda)}\). Since \(d_g(p,q)\leq l\), this gives (5.2.17).
If the weighted minimizer is not realized, take a minimizing sequence. The usual Calabi limiting argument gives a broken minimizing object made of finite minimizing segments, weighted minimizing rays, and weighted minimizing lines. At the point where the corresponding excess vanishes, replace any ray by the point at parameter \(t\) on that ray and use the finite-segment barrier above. The right hand side contains the term \(-(m-1)\lambda t/2\) for that ray and is negative for \(t\) sufficiently large, contradicting the local minimum of the excess. Thus the non-realized case cannot occur, and the same diameter bound holds for all pairs of points. Hopf–Rinow then implies compactness. ◻
Let \((M^m,g)\) be complete, \(m\geq3\), and suppose \(u\gt{}0\) satisfies (5.2.6) with
If
then
In particular \(M\) is compact.
Proof. Because \(u\) is bounded above and below, the weighted metric \(u^{2\alpha}g\) is complete, so \(L_u^\alpha\)-minimizers exist. Let \(\alpha:[0,l]\to M\) be an \(L_u^\alpha\)-minimizer from \(p\) to \(q\), parametrized by \(g\)-arclength, and let \(x=\alpha(l/2)\). As above, the weighted excess has a local minimum at \(x\).
Use (5.2.9) on each half of \(\alpha\) with
Since \(\alpha(m-3)/(m-1)\geq0\), we estimate the positive term by \(u_+^{\frac{m-3}{m-1}\alpha}\) and the negative term by \(u_-^{\frac{m-3}{m-1}\alpha}\). Thus
Hence
Since \(d_g(p,q)\leq l\) and \(p,q\) were arbitrary, this proves (5.2.18). Compactness follows from Hopf–Rinow. ◻
Volume estimate.
Assume the hypotheses of Theorem 5.2.13 and normalize \(\min_{\widetilde N}\tilde u=1\). Set \(\theta=2\alpha/(n-1)\) and define, on \(\widetilde N\),
Then \(I\) satisfies
in the viscosity sense.
Proof. By the diameter part, \(\widetilde N\) is compact; hence the minimizer \(E\) exists for every \(v_0\in(0,\int_{\widetilde N}\tilde u^\theta)\). We suppress tildes. Put
Let \(\Sigma=\partial E\) and take a smooth normal variation with variational field \(\varphi\nu\). We extend \(\varphi\) to a neighborhood of \(\Sigma\) and use the same symbol for the extension. With the convention used here,
Also
Thus
and differentiating this last expression gives the following formula. In the following displays, the same color marks the terms with the same origin: magenta terms cancel by integration by parts or by the normal derivative of \(\varphi=u^{-\alpha}\); green terms are the spectral-Ricci pair; blue terms come from \(|A_\Sigma|^2\); red terms come from \(u_\nu^2\); orange terms come from \(Hu_\nu\); and purple terms come from the surviving part of the last line.
The last line is just the derivative of the factor \(u^\alpha\varphi\,d\mu_t\) in \(A'(t)\), rewritten with a factor \(u^\theta\):
The volume constraint implies that
where \(A_v\) is the area of this variation written as a function of \(V\). Choose \(\varphi=u^{-\alpha}\) and set
Then \(H=X-\alpha Y\). For \(\varphi=u^{-\alpha}\), the tangential \(\Delta^\Sigma u\) term cancels after integration by parts with the tangential gradient term
Hence the first two lines of (5.2.21), together with (5.2.3) and \(|A_\Sigma|^2\geq H^2/(n-1)\), are bounded above by
The last line of (5.2.21) is
because \(\class{note-ax-cancel}{\varphi_\nu=-\alpha u^{-\alpha}Y}\) and \(\class{note-ax-last}{H+\alpha Y=X}\). Therefore
Expanding \(H=X-\alpha Y\) gives
The inverse-function chain rule gives
Substituting the formulas for \(V',V''\) and using \(\theta=2\alpha/(n-1)\) yields
Here we used \(\alpha\leq(n-1)/(n-2)\) and \(u\geq1\). Holder’s inequality gives
Thus
Since \(A_v\) is an upper barrier for \(I\) at \(v_0\), this is exactly the viscosity inequality (5.2.20). ◻
Let \(V\in(0,\infty]\) and let \(I:[0,V)\to\mathbb R\) be continuous with \(I(0)=0\) and \(I(v)\gt{}0\) for \(v\in(0,V)\). Suppose
in the viscosity sense on \((0,V)\), and suppose
Then
Proof. Set
Applying the chain rule to positive upper test functions for \(I\), the preceding viscosity inequality is equivalent to
in the viscosity sense. The small-volume assumption gives
For \(\zeta\gt{}0\) define
and define the model profile \(I_\zeta\) by
Let \(\psi_\zeta=I_\zeta^{n/(n-1)}\). Since
direct differentiation gives
The existence interval of \(I_\zeta\) has length
For \(\zeta=|S^{n-1}|\), this is exactly \(\lambda^{-n/2}|S^n|\).
Assume by contradiction that \(V\gt{}\lambda^{-n/2}|S^n|\). Choose \(\zeta\gt{}|S^{n-1}|\) so close to \(|S^{n-1}|\) that \(V_\zeta\lt{}V\). Then \((\psi_\zeta)'_+(0)\gt{}\psi'_+(0)\), so \(\psi\lt{}\psi_\zeta\) on \((0,\delta)\) for some \(\delta\gt{}0\). If the two functions first meet at \(a\in(0,V_\zeta)\), then on \((0,a)\) we have \(\psi\lt{}\psi_\zeta\). Since the function \(s\mapsto -n\lambda s^{(2-n)/n}\) is increasing on \((0,\infty)\), the difference \(w=\psi-\psi_\zeta\) satisfies \(w''\lt{}0\) in the viscosity sense on \((0,a)\). Thus \(w\) is strictly concave there. But \(w(0)=w(a)=0\) and \(w\lt{}0\) on \((0,a)\), which is impossible for a concave function. Hence \(\psi\lt{}\psi_\zeta\) on \((0,V_\zeta)\). Since \(\psi_\zeta(V_\zeta)=0\) while \(V_\zeta\lt{}V\) and \(I\gt{}0\) on \((0,V)\), continuity gives a contradiction at \(V_\zeta\). Therefore \(V\leq \lambda^{-n/2}|S^n|\). ◻
Proof. Normalize \(\min_{\widetilde N}\tilde u=1\) and set
The profile \(I\) satisfies (5.2.20). Since \(\tilde u\) attains its minimum at some point \(\tilde p\), small geodesic balls centered at \(\tilde p\) satisfy
Since these balls are admissible competitors for \(I\), it follows that
Lemma 5.2.19 applied with \(V=V_0\) therefore gives
Since \(\tilde u\geq1\), we have
If equality holds, then \(\int_{\widetilde N}\tilde u^\theta=|\widetilde N|\) and \(\tilde u\geq1\), hence \(\tilde u\equiv1\). The spectral inequality becomes the pointwise Ricci bound \(\mathrm{Ric}_{\widetilde N}\geq(n-1)\lambda\), and the equality case in the classical Bishop–Gromov theorem gives that \(\widetilde N\) is the round sphere of radius \(\lambda^{-1/2}\). ◻
We need a comparison of distance.
Let \(\varphi:M\to \mathbb{R}^{n+1}\) be the immersion and \(\tilde{g}=r^{-2}g\) and \(g=\varphi^*(\delta)\) with \(0 \in M\). Given two points \(p,q\in M\) with \(d_{\tilde{g}}(p,q)\leq D\), we have \(r(p)\leq e^{D}r(q)\).
Proof. Let \(\alpha\) be a curve joining \(p\) and \(q\) with length \(D+\varepsilon\). Then, we have
◻
Proof. Let \(M^n\hookrightarrow\mathbb{R}^{n+1}\) be as in the theorem, where \(n=3\) or \(n=4\). We fix any point \(x_0\in M\) and suppose \(x_0=0\) after a translation. Let \(\tilde{g}=r^{-2}g\), where \(r(x)=|x|\).
The preceding spectral estimates and \(\mu\)-bubble constructions give the following dimension-dependent constants. There exist \(L_n,A_n,D_n\lt{}\infty\) such that, whenever \(N\) is a compact collar in \((M,\tilde{g})\) with \(d_{\tilde{g}}(\partial_-N,\partial_+N)\geq L_n\), one can find a smooth \(\mu\)-bubble component \(\Sigma\) which separates \(\partial_-N\) from \(\partial_+N\), lies in \(\tilde B_{L_n}(\partial_-N)\), and satisfies
For \(n=3\) and \(n=4\) this follows from the \(\mu\)-bubble reduction in Theorem 5.2.8 together with the spectral Ricci estimates in §5.2.6.
For any \(\rho\gt{}0\), choose \(R\) large such that
Set \(N=B_R^M\setminus B_\rho^M\), with \(\partial_-N=\partial B_\rho^M\) and \(\partial_+N=\partial B_R^M\), and apply the preceding paragraph. If \(x\in\Sigma\), then there is \(y\in\partial B_\rho^M\) with \(d_{\tilde{g}}(x,y)\leq L_n\). By the distance comparison lemma,
Therefore \(\Sigma\subset B_{C_n\rho}\) in the Euclidean metric. Since \(g=r^2\tilde{g}\), the induced measures on the \((n-1)\)-dimensional hypersurface \(\Sigma\) satisfy \(d\mu_g=r^{n-1}d\mu_{\tilde{g}}\), and hence
Since \(M\) is simply connected and has one end [CSZ97], the side of \(\Sigma\) containing \(B_\rho^M(x_0)\) is a compact region. Let \(\Omega_\rho\) denote this region; then \(B_\rho^M(x_0)\subset\Omega_\rho\) and \(\partial\Omega_\rho=\Sigma\). The Michael–Simon isoperimetric inequality for minimal submanifolds [MS73] gives
Consequently,
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Mazet’s proof in the ambient space \(\mathbb{R}^6\)
Here \(\mathbb{R}^6\) means the hypersurface dimension is \(5\). Mazet [Maz24] proves that every complete, connected, two-sided stable minimal immersion
is flat. The proof follows the Chodosh–Li–Minter–Stryker strategy [CLMS25], but with one extra parameter in the curvature quantity. This extra parameter is the weighted bi-Ricci curvature.
Let \((N^m,g)\) be a Riemannian manifold, and let \(\{e_1,\ldots,e_m\}\) be an orthonormal basis. For \(\alpha\in\mathbb{R}\), Mazet defines the \(\alpha\)-weighted bi-Ricci curvature by
Its pointwise minimum is
When \(\alpha=1\), this is the usual bi-Ricci curvature:
Thus \(\alpha\) lets one change the relative weight of the curvature directions which are tangent to the eventual \(\mu\)-bubble.
The first step is the same conformal change as before. Remove the points where the immersion hits the origin and set
The Gulliver–Lawson observation is that \((N,\tilde g)\) is complete. Mazet’s main spectral estimate says that, in dimension \(5\), one can choose
so that the stability inequality implies the following weighted bi-Ricci spectral lower bound:
Equivalently,
So \((N,\tilde g)\) does not have a pointwise lower bound \(\widetilde{\Lambda}_\alpha\geq\delta\), but it has the corresponding spectral lower bound.
The second step is to build a weighted \(\mu\)-bubble in a long annulus of \((N,\tilde g)\). The bubble is a hypersurface
which separates the inner and outer boundary of the annulus. The second variation of the weighted \(\mu\)-bubble turns the spectral \(\operatorname{BRic}_\alpha\) bound on \(N\) into a spectral Ricci bound on \(\Sigma\). More precisely, if
then the induced metric on \(\Sigma\) satisfies an inequality of the form
For Mazet’s parameters,
This is the numerical point that allows the Antonelli–Xu spectral Bishop–Gromov theorem [AX24] to be applied to the \(4\)-dimensional bubble. It gives a uniform \(\tilde g\)-volume bound for \(\Sigma\).
Finally one returns to the original metric \(g\). If \(\Sigma\) is chosen around \(B_\rho^M(p_0)\), the conformal collar bound gives
so the \(\tilde g\)-volume bound for \(\Sigma\) becomes a \(g\)-area bound
Since \(M\) has one end, one can choose the relevant component of \(\Sigma\) to enclose \(B_\rho^M(p_0)\). The Michael–Simon–Brendle isoperimetric inequality [MS73, Bre21] on minimal hypersurfaces then gives
This is the Euclidean volume growth needed by the Schoen–Simon–Yau stable Bernstein theorem. Hence \(M^5\) is flat. In short, the new feature in \(\mathbb{R}^6\) is that the weighted curvature \(\operatorname{BRic}_{40/43}\) creates just enough spectral Ricci positivity on the \(4\)-dimensional \(\mu\)-bubble for Antonelli–Xu’s volume estimate to close.